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7 March, 18:08

A potassium hydroxide (KOH) solution has a molar concentration of 0.065 M, calculate the [H3O+], [OH-] and pH of the solution.

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  1. 7 March, 19:04
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    1) [OH⁻] = 0.065 M

    2) [H₃O⁺] = 1.54 x 10⁻¹³ M.

    3) pH = 12.81.

    Explanation:

    HCl is completely dissociated yo its ions in solution:

    KOH + H₂O → H₃O⁺ + K⁺ + OH⁻,

    1) [OH⁻] = 0.065 M.

    2) [H₃O⁺]:

    ∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

    ∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴ / (0.065 M) = 1.54 x 10⁻¹³ M.

    3) pH:

    For strong acids like HCl:

    pH = - log[H₃O⁺] = - log[1.54 x 10⁻¹³ M] = 12.81.
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