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13 February, 16:56

Calculate the mass of nickel metal which will react with 25mL of 0.15mol/L (

hydrochloric acid to produce nickel (II) chloride. 0.110625g

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  1. 13 February, 17:36
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    0.110625 g of Ni

    Explanation:

    The first step in solving this problem is to put down the accurate chemical reaction equation.

    Ni (s) + 2HCl (aq) - --> NiCl2 (aq) + H2 (g)

    Secondly, we obtain the amount of HCl that reacted from the information provided.

    Volume of HCl (V) = 25 ml

    Concentration of HCl (C) = 0.15 mol/L

    Then, to find the number of moles of HCl (n);

    n = CV

    Substitution values

    n = 25/1000 * 0.15

    n = 3.75 * 10^-3 moles

    Mass of 3.75 * 10^-3 moles of HCl = number of moles * molar mass

    Molar mass of HCl = 36.5 gmol-1

    Therefore;

    Mass of HCl = 3.75 * 10^-3 moles * 36.5 gmol-1

    Mass of HCl = 0.136875 g of HCl

    Thirdly we determine the mass of Ni reacted;

    If 1 mole of Ni reacted with 2 moles of HCl according to the reaction equation

    Then x moles of Ni reacts with 3.75 * 10^-3 moles of HCl

    x = 1 * 3.75 * 10^-3 moles / 2

    x = 1.875 * 10^-3 moles of Ni

    Mass of Ni = 1.875 * 10^-3 moles of Ni * 59 gmol-1

    Mass of Ni = 0.110625 g of Ni
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