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18 February, 04:05

Consider the reaction: 2 SO2 (g) + O2 (g) 2 SO3. If, at equilibrium at a certain temperature, [SO2] = 1.50 M, [O2] = 0.120 M, and [SO3] = 1.25 M, what is the value of the equilibrium constant? none of the above 8.68 6.94 0.14 5.79

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  1. 18 February, 04:27
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    5.79

    Explanation:

    The following data were obtained from the question:

    Concentration of SO2, [SO2] = 1.50 M

    Concentration of O2, [O2] = 0.120 M

    Concentration of SO3, [SO3] = 1.25 M

    Equilibrium constant, (K) = ... ?

    The balanced equation for the reaction is given below:

    2SO2 (g) + O2 (g) 2SO3 (g)

    From the balanced equation, the equilibrium constant K is written as follow:

    K = [SO3]² / [SO2]²• [O2]

    With the above, the value of the equilibrium constant, K can be obtained as follow

    K = [SO3]² / [SO2]²• [O2]

    K = (1.25) ² / (1.50) ² * 0.120

    K = 1.5625 / (2.25 x 0.120)

    K = 5.79

    Therefore, the equilibrium constant is 5.79.
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