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17 May, 09:46

Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order of increasing polarity.

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  1. 17 May, 11:39
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    The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

    1) In SCl2 we have the S-Cl bond

    Electronegativity values: S = 2.5, Cl = 3

    Difference = 3.0 - 2.5 = 0.5

    2) In F2 we have the F-F bond

    Electronegativity value: F = 4.0

    Difference = 4.0-4.0 = 0

    3) In CS2 we have the C-S bond

    Electronegativity value: C = 2.5, S = 2.5

    Difference = 2.5 - 2.5 = 0

    4) In CF4 we have the C-F bond

    Electronegativity values: C = 2.5, F = 4.0

    Difference = 4.0 - 2.5 = 1.5

    5) In BrCl we have the Br-Cl bond

    Electronegativity values: Br = 2.8, Cl = 3

    Difference = 3.0 - 2.8 = 0.2

    Therefore, the increasing order of polarity is

    F2 = CS2 < BrCl < SCl2 < CF4
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