Ask Question
5 November, 23:10

For 2Na (s) + Cl2 (g) - 2NaCI (s), how many grams of sodium Chloride will be made from 115 g of sodium metal when reacted with excess chlorine gas?

+2
Answers (1)
  1. 6 November, 01:49
    0
    Given:

    Mass of Na = 115 g

    Excess Cl2

    To determine:

    Mass of NaCl produced

    Explanation:

    Given reaction is-

    2Na (s) + Cl2 (g) → 2NaCl (s)

    Since Cl2 is in excess, Na will be the limiting reagent

    As per the reaction stoichiometry Na:NaCl = 1:1

    i. e. moles of Na reacted = moles of NaCl formed

    Now, # moles of Na = mass of Na/atomic mass

    = 115 g/23 g. mol-1 = 5 moles

    Therefore, moles of NaCl = 5

    Molar mass of NaCl = 58 g/mol

    Mass of NaCl = 5 moles * 58 g. mol-1 = 290 g

    Ans: Amount of Nacl produced = 290 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “For 2Na (s) + Cl2 (g) - 2NaCI (s), how many grams of sodium Chloride will be made from 115 g of sodium metal when reacted with excess ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers