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Chemistry
Mylee Chase
30 March, 14:14
Number of O atoms in 7.3 x10^-3 g of CaSO4 x 2H2O
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Braeden Maynard
30 March, 15:13
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The number of O atoms in 7.3 x10 ^-3 g of CaSO4 x 2H2O are = 1.535 x10^20 atoms
calculation
step 1: calculate the moles of CaSO4. 2H2O
moles = mass/molar mass molar mass is of CaSO4. H2O=Mw of Ca + S + O + H2O = 40+32 + (4x16) + 2 ((1x2) + 16) = 172 g/mol
moles is therefore = 7.3 x10^-3 g/172 g/mol = 4.244 x10^-5 moles find the moles of O since there are 6 atoms of O the moles of O = 6 x (4.244 x10^-5) = 0.000255 moles
by use of Avogadro's law constant find the number of O atom that is 1 mole = 6.02 x10 ^23 atoms
0.000255 moles=? atoms
by cross multiplication = 0.000255 moles x (6.02 x10^23 atoms) / 1 mole = 1.535 x10^20 atoms
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