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3 October, 05:43

What is the molarity of 500 ml of a solution containing 85.0g AgNO3? A) 0.5 M B) 1.0 M C) 2.0 M D) 5.0 M

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  1. 3 October, 06:52
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    Consider the equation for calculating molarity: (no. of mole of solute) : (volume of solution)

    First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass

    no. of mole of 85.0g of AgNO3 = 85.0 / (107.9+14.0+16.0x3)

    =0.5mol

    Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.

    Volume of solution = 500/1000

    = 0.5 dm3

    Therefore, the molarity is

    0.5/0.5

    =1.0M

    The answer should be B.
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