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14 April, 03:04

What is the mole fraction of LiCl in a mixture of 0.564 g NaCl, 1.52 f KCl and 0.857 g LiCl?

Molar Mass

NaCl: 58.44 g/mol

KCl: 74.55 g/mol

LiCl: 42.39 g/mol

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Answers (1)
  1. 14 April, 06:39
    0
    Mole fraction of LiCl = 0.4

    Explanation:

    Given dа ta:

    Mass of NaCl = 0.564 g

    Mass of KCl = 1.52 g

    Mass of LiCl = 0.857 g

    Mole friction of LiCl = ?

    Solution:

    First of all we will calculate the moles of each compound.

    Moles of NaCl:

    Moles of NaCl = mass / molar mass

    Moles of NaCl = 0.564 g / 58.44 g/mol

    Moles of NaCl = 0.01 mol

    Moles of KCl:

    Moles of KCl = mass / molar mass

    Moles of KCl = 1.52 g / 74.55 g/mol

    Moles of KCl = 0.02 mol

    Moles of LiCl:

    Moles of LiCl = mass / molar mass

    Moles of LiCl = 0.857 g / 42.39 g/mol

    Moles of LiCl = 0.02 mol

    Mole fraction of LiCl:

    Mole fraction of LiCl = moles of LiCl / total moles of mixture

    Total number of moles = 0.02+0.02+0.01 = 0.05

    Mole fraction of LiCl = 0.02/0.05 = 0.4
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