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9 August, 07:53

Calculate the molarity of a solution prepared by dissolving 9.8 moles of solid NaOH in enough water to make 3.62 L of solution

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Answers (2)
  1. 9 August, 09:58
    0
    A solution of 9.8 moles NaOH in 3.62 L has a molarity of 2.7 M

    Explanation:

    Step 1: Data given

    Number of moles solid NaOH = 9.8 moles

    Volume = 3.62 L

    Step 2: Calculate molarity of NaOH

    Molarity = moles / volume

    Molarity NaOH = moles NaOH / volume

    Molarity NaOH = 9.8 moles / 3.62 L

    Molarity of NaOH solution = 2.7 mol / L = 2.7 M

    A solution of 9.8 moles NaOH in 3.62 L has a molarity of 2.7 M
  2. 9 August, 11:27
    0
    2.71mol/L

    Explanation:

    Step 1:

    Data obtained from the question. This includes:

    Mole of solute = 9.8 moles

    Volume = 3.62L

    Molarity = ?

    Step 2:

    Determination of the molarity.

    Molarity is simply the mole of solute per unit litre of the solution. It is represented by the following equation:

    Molarity = mole of solute / Volume of solution

    Molarity = 9.8 mole / 3.62L

    Molarity = 2.71mol/L
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