Which of the following is a valid mole ratio from the balanced equation 2C3H6 + 9O2 → 6CO2 + 6H2O?

1 mole of C3 H6 / 2 moles of C O2

6 moles of H2 O / 9 moles of O2

2moles of C3 H6 / 6 moles of O2

3 moles of H2 O / 2 moles of C O2

6 mol H20/9 mol O2

Explanation:

I just took the test and got it right.

6 moles of H₂O / 9 moles of O₂

Explanation:

The Balance Chemical Equation is as follow,

2 C₃H₆ + 9 O₂ → 6 CO₂ + 6 H₂O

According to this balance equation 2 moles of C₃H₆ (Propene) when combusted with 9 moles of O₂ (Oxygen) produces 6 moles of CO₂ (Carbon Dioxide) and 6 moles of H₂O (Water Vapors).

Hence, Given options are;

1 mole of C₃H₆ / 2 moles of CO₂: This is incorrect because 1 mole of C₃H₆ will produce 2 moles of CO₂.

6 moles of H₂O / 9 moles of O₂: This is correct as 6 moles of H₂O is produced by reacting 9 moles of O₂.

2 moles of C₃H₆ / 6 moles of O₂: This ratio is incorrect because for complete oxidation 2 moles of C₃H₆ requires 9 moles of O₂.

3 moles of H₂O / 2 moles of CO₂: This is also incorrect because the production of 3 moles of H₂O will be accompanied by the production of 3 moles of CO₂.