Aluminum sulfate is analyzed, and the sample contains 0.0670 moles of sulfate ions. How many moles of aluminum are in the sample?

0.0447 moles of Aluminum

Explanation:

Break this down to an ionic equation (which may not exist in the real world but it will give you the mol ratios).

Al2 (SO4) 3 = ==> 2Al^ (+3) + 3 SO4^ (-2)

Now write the equation showing the actual number of moles of SO4^ (-2) present. Indicate the Al moles with an x

Al2 (SO4) 3 = ==> 2Al^ (+3) + 3 SO4^ (-2)

x 0.0670

Now set up a proportion

2/x = 3/0.0670 Cross multiply

2*0.0670 = 3x Simplify the left

0.134 = 3x Divide both sides by 3

0.134/3 = 3x/3 Divide

0.0447 = x

there are 0.0447 moles of Aluminum