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14 August, 16:40

insert the missing coefficients in the following partially balanced chemical equations S+6HNO=HSO4+NO+H2O

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  1. 14 August, 20:15
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    S + 6HNO₃ ⟶ H₂SO₄ + 6NO₂ + 2H₂O

    Step-by-step explanation:

    S + 6HNO₃ ⟶ H₂SO₄ + NO₂ + H₂O

    One way is to balance this equation is the oxidation number method.

    Step 1. Calculate the oxidation number of every atom:

    S⁰ + H⁺¹N⁺⁵O₃⁻² ⟶ H₂⁺¹S⁺⁶O₄⁻² + N⁺⁴O₂⁻² + H₂⁺¹O⁻²

    Step 2. Identify the changes in oxidation number:

    S: + 0 ⟶ + 6; Change = + 6

    N: + 5 ⟶ + 4; Change = - 1

    Step 3. Equalize the changes in oxidation number.

    You need 6 atoms of N for every 1 atom of S. This gives us total changes of - 6 and + 6.

    Step 4. Insert coefficients to get these numbers.

    1S + 6HNO₃ ⟶ 1H₂SO₄ + 6NO₂ + H₂O

    Step 5. Balance O.

    We have fixed 18 O on the left and 16 O on the right. We need 2 more O on the right. Put a 2 in front of H₂O.

    1S + 6HNO₃ ⟶ 1H₂SO₄ + 6NO₂ + 2H₂O

    Every formula now has a coefficient. The equation should be balanced.

    Step 6. Check that all atoms balance.

    Atom Left-hand side Right-hand side

    S 1 1

    H 6 6

    N 6 6

    O 18 18

    The balanced equation is

    S + 6HNO₃ ⟶ H₂SO₄ + 6NO₂ + 2H₂O
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