What is the net ionic equation of the reaction of zncl2 with naoh?

ZnCl₂ + 2NaOH → Zn (OH) ₂↓ + 2NaCl

Explanation:

ZnCl₂ reacts with NaOH to produce a white precipitate of Zn (OH) ₂ and NaCl. The net ionic equation of the reaction is:

ZnCl₂ + 2NaOH → Zn (OH) ₂↓ + 2NaCl

The met ionic equation is zero.

Explanation:

Zn²⁺ 2Cl⁻ + 2Na⁺ + 2OH⁻ → Zn²⁺ + 2OH⁻ + 2Na⁺ + 2Cl⁻

We'll then cancel out ions that are present in both reactant and product phase.

Zn²⁺ will cancel out each other from both sides.

2Cl⁻ will cancel out each other from both sides.

2Na⁺ will cancel out each other from both sides.

2OH⁻ will cancel out ewch other from both sides.

Leaving the net ionic equation zero (0).