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18 October, 00:25

Calculate [h+] for a solution in which [oh-] is 100 times greater than [h+].

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  1. 18 October, 02:22
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    [H⁺] = 10⁻⁸.

    Explanation:

    We have that the product of [H⁺] and [OH⁻] is equal to 10⁻¹⁴.

    [H⁺][OH⁻] = 10⁻¹⁴.

    We have that [OH⁻] is 100 times greater than [H⁺], [OH⁻] = 100[H⁺].

    ∵ [H⁺][OH⁻] = 10⁻¹⁴.

    ∴ [H⁺].100[H⁺] = 10⁻¹⁴.

    ∴ 100 [H⁺]² = 10⁻¹⁴.

    ∴ [H⁺]² = 10⁻¹⁴ / 100 = 10⁻¹⁶.

    ∴ [H⁺] = √ (10⁻¹⁶) = 10⁻⁸.

    So, [OH⁻] = 10⁻⁶.
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