How many moles of NH3 from when 32.4 L of H2 gas completely reacts at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP
N₂ (g) + 3H₂ (g) →2NH₃ (g)
ps: We have to not only give the answer which is 1.45 mol NH3 but we have to show the equation of how we got to it.
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