Solid urea, CN2OH4, (MM=60.06 g) and liquid water are produced by heating ammonia

(MM=17.03 g) gas and carbon dioxide (MM=44.01 g) gas according to the equation

below. This reaction is known to proceed with a percent yield of 85.5%. What is the

theoretical yield if 13.74 g of urea is actually collected?

2NH3 (g) + CO2 (g) →CN2OH4 (s) + H2O (1)

Question

Chemistry

Jorge Randall

30 September, 06:04

Solid urea, CN2OH4, (MM=60.06 g) and liquid water are produced by heating ammonia

(MM=17.03 g) gas and carbon dioxide (MM=44.01 g) gas according to the equation

below. This reaction is known to proceed with a percent yield of 85.5%. What is the

theoretical yield if 13.74 g of urea is actually collected?

2NH3 (g) + CO2 (g) →CN2OH4 (s) + H2O (1)

+2

Answers (1)

Know the Answer?

Tommy Floyd · Answer 1

16.1 g

Explanation:

Percent yield = (actual / theoretical) x 100

85.5 = (13.74 / theoretical) x 100

0.855 = (13.74 / theoretical)

0.855 (theoretical) = 13.74

theoretical = 13.74 / 0.855

Theoretical = 16.070 = 16.1 g (3 sig figs)