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17 February, 20:22

How many moles of molecular oxygen will be needed for the complete combustion of 100.0 g of sulfur dioxide? The product of this reaction is sulfur trioxide

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  1. 17 February, 23:40
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    0.78 mol O2

    Explanation:

    2SO2 + O2 - > 2 SO3

    64 g SO2 - > 1 mol SO2

    100 g SO2 - > x

    x = (100 g SO2 * 1 mol SO2) / 64 g SO2 x=1.56 mol SO2

    1 mol O2 - > 2 mol SO2

    x - > 1.56 mol SO2

    x = (1.56 mol SO2 * 1 mol O2) / 2 mol SO2 x=0.78 mol O2
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