Nickel-Iron Battery

In1901, Thomas Edison invented the nickel-iron battery. The following reaction takes place in the battery.

Fe (s) + 2NiO (OH) (s) + 2H2O (1) - > Fe (OH) 2 (s) + 2Ni (OH) 2 (aq)

How many mol of Fe (OH) 2 is produced when 5.00 mol of Fe and 8.00 mol of NiO (OH) react?

The answer is: 4.00 mol of Fe (OH) 2 is produced.

Balanced chemical reaction:

Fe (s) + 2NiO (OH) (s) + 2H₂O (l) → Fe (OH) ₂ (s) + 2Ni (OH) ₂ (aq).

n (Fe) = 5.00 mol; amount of iron.

n (NiO (OH)) = 8.00 mol; amount of nickel oxide hydroxide, limiting reactant.

From chemical reaction: n (NiO (OH)) : n (Fe (OH) ₂) = 2 : 1.

n (Fe (OH) ₂) = 8 mol : 2.

n (Fe (OH) ₂) = 4 mol; amount of iron (II) hydroxide.

4.0 moles of Fe (OH) ₂.

Explanation:

It is a stichiometry problem. The balanced equation: Fe + 2NiO (OH) + 2H₂O → Fe (OH) ₂ + 2Ni (OH) ₂, It is clear that 1.0 mole of Fe reacts with 2.0 moles of NiO (OH) and 2.0 moles of H₂O to produce 1.0 mole of Fe (OH) ₂ and 2.0 moles of Ni (OH) ₂. The given dа ta: 5.00 moles of Fe reacts with 8.00 mol of NiO (OH). From the stichiometry; 4.0 moles of Fe (1.0 mole will be in excess) reacts completely with 8.0 moles of NiO (OH) and produce 4.0 moles of Fe (OH) ₂.