A student is running an experiment in which 74.8 grams of bai2 is needed, but the only jar of reagent in the lab is labelled barium iodide dihydrate. how many grams of the hydrate must the student weigh out in order to get the desired amount of the anhydrous compound? 3

The number of grams of hydrated that student must weigh out in order to get desired amount of the anhydrous compound is 81.68 grams

Calculation

find the molar mass of Bai2 and molar mass of barium iodide dihydrate

that is Bai2 = 137.3 + (2x127) = 391.3 g/mol

Bai2. 2H2O = 137.3 + (2 x127) + 2 (2+16) = 427.3g/mol

using ratios and letting the mass of hydrate be represented by Y

427.3/391.3=Y/74.8

multiply both side by 74.8

Y=81.68 grams