Suppose you have 0.100 m3 of co2, at pressure of 2.00 atm, and a temperature of 30.0? c. How many grams of co2 do you have? Express your answer in grams.

You would use the ideal gas equation which is Pv=nRt (r=constant=8.314) and (n=moles) and once you've found the number of moles you'd do mass = moles * r

P=2 atmospheres (we need this in pascals)

So 2*101325 = 202650pa

And we need temperature in kelvin

30+273=303c

Rearrange the ideal gas equation to find moles

n=Pv/nRt

n=202650*0.1/8.314*303

n = 8.044405595

Mass = 8.04*44 (molar mass of CO2)

= 352g

If you're American you would do this differently as I'm a 16 year old at college in the UK

You would keep the atmospheres at 2 but you would change the volume to litres = 100L and you would use the atmospheres gas constant = 0.0821

n = 2*100/0.0821*303

n=8.039780836

Mass = 8.04*44

=354g

There is a slight variation in both but that is normal if you're American use the 2nd answer