Ask Question
6 September, 09:03

15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl calculated in grams?

+3
Answers (1)
  1. 6 September, 12:14
    0
    41.56 g

    Explanation:

    Given dа ta:

    Mass of NH₄Cl = 15.50 g

    Actual yield of AgCl = 35.50 g

    Theoretical yield of AgCl = ?

    Solution:

    Chemical equation:

    NH₄Cl + AgNO₃ → AgCl + NH₄NO₃

    Number of moles of NH₄Cl:

    Number of moles = mass / molar mass

    Number of moles = 15.50 g / 53.491 g/mol

    Number of moles = 0.29 mol

    Now we will compare the moles of NH₄Cl with AgCl.

    NH₄Cl : AgCl

    1 : 1

    0.29 : 0.29

    Theoretical yield of AgCl:

    Mass = number of moles * molar mass

    Mass = 0.29 mol * 143.32 g/mol

    Mass = 41.56 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl calculated ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers