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30 June, 12:08

How many grams are there in 7.4 x 1023 molecules of H2SO4?

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  1. 30 June, 12:36
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    7.4x10^23 = molecules of silver nitrate sample

    6.022x10^23 number of molecules per mole (Avogadro's number)

    Divide molecules of AgNO3 by # of molecules per mol

    7.4/6.022 = 1.229 mols AgNO3 (Sig Figs would put this at 1.3)

    (I leave off the x10^23 because they both will divide out)

    Use your periodic table to find the molar weight of silver nitrate.

    107.868 (Ag) + 14 (N) + 3 (16[O]) = 169.868g/mol AgNO3

    Now multiply your moles of AgNO3 with your molar weight of AgNO3

    1.229mol x 169.868g/mol = 208.767g AgNO3
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