A sample of hydrogen exerts a pressure of 0.329 atm at 47 C. What will the pressure be at 77 C, assuming constant Volume?

P

2

=

0.360

a

t

m

Explanation:

Assuming that Hydrogen is behaving ideally, therefore, we can use the ideal gas law:

P

V

=

n

R

T

Since the gas is being heated only and the volume is not changing, therefore, n and V are constant and therefore we can say:

P

T

=

k

where

k

=

n

R

V

is a constant value that does not change during the process.

Thus,

P

1

T

1

=

P

2

T

2

This is called Gay-Lussac law.

⇒

P

2

=

P

1

T

1

*

T

2

⇒

P

2

=

0.329

a

t

m

320

K

*

350

K

=

0.360

a

t

m

P^2 = 0.360atm

(ask for work if needed)