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30 August, 09:07

0.100g of Cu (OH) 2 was added to a beaker which was filled to the 3.00L mark with water. what is the pOH of the solution

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  1. 30 August, 12:52
    0
    3.466

    Explanation:

    First calculate the molarity using mass and volume

    Mass = 0.100 g of Cu (OH) 2

    Volume = 3.00 L

    Find molar mass of solute as : 63.546 + (15.9994+1.00794) * 2 = 97.56068 g/mol

    Convert grams to moles as; 0.100/97.56068 = 0.0010250031 moles

    Determine molarity = 0.0010250031/3.00 = 0.0003416677 M Cu (OH) 2

    pOH = - log [OH⁻]

    pOH = - log [0.0003416677]

    pOH = 3.466
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