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7 May, 12:47

For each reaction, identify the substance being oxidized and the substance being reduced.? A.) Mg (s) + Br2 (g) →MgBr2 (s) substance being oxidized: substance being reduced: B.) 2Cr3 + (aq) + 3Mn (s) →2Cr (s) + 3Mn2 + (aq) substance being oxidized: substance being reduced: C.) 2H + (aq) + Ni (s) →H2 (g) + Ni2 + (aq) substance being oxidized: substance being reduced:

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  1. 7 May, 15:16
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    These are three questions each with its complete answer.

    A.) Mg (s) + Br₂ (g) → MgBr₂ (s)

    Answer:

    substance being oxidized: Mg substance being reduced: Br

    Explanation:

    1) Determine the oxidation states of all the elements

    a) Reactant side:

    Mg (s) : 0, since the oxidation state of pure elements is zero

    Br₂: 0, since the oxidation state of pure elements is zero

    b) Product side:

    MgBr₂ (s):

    Br, such as the other halogens, form metal halides with oxidation state - 1

    Mg, such as other earth alkalyn metals, use oxidation state + 2

    Verify that the compound is neutral: 2 (-1) + 2 = 0.

    2) Look at the changes:

    Mg passed from 0 to + 2. Increase on the oxidation state means oxidation.

    Br passed from 0 to - 1. Decrease on the oxidation state means reduction.

    Conclusion:

    Substance being oxidized: Mg

    Substance being reduced: Br

    B.) 2Cr³⁺ (aq) + 3Mn (s) → 2Cr (s) + 3Mn²⁺ (aq)

    Answer:

    substance being oxidized: Mn substance being reduced: Cr

    Explanation:

    1) Determine the oxidation states of all the elements

    a) Reactant side:

    Cr: + 3, since it is indicated as a superscript to the right of the symbol.

    Mn: 0, since the oxidation state of pure elements is zero

    b) Product side:

    Cr: 0, since the oxidation state of the pure elements is zero.

    Mn: + 2, since it is indicated as s superscript to the right of the atom.

    2) Look at the changes:

    Cr passed from + 3 to 0. Decrease on the oxidation state means reduction.

    Mn passed from 0 to + 2. Increase on the oxidation state means oxidation.

    Conclusion:

    Substance being oxidized: Mg

    Substance being reduced: Br

    C.) 2H⁺ (aq) + Ni (s) → H₂ (g) + Ni²⁺ (aq)

    substance being oxidized: Ni substance being reduced: H

    1) Determine the oxidation states of all the elements

    a) Reactant side:

    H: + 1, since it is understood a number 1 in front of the + symbol to rright of the chemical symbol.

    Ni: 0, since the oxidation state of pure elements is zero

    b) Product side:

    H₂ (g) : 0, since the oxidation state of the pure elements is zero.

    Ni: + 2, since it is indicated as s superscript to the right of the ion.

    2) Look at the changes:

    H passed from + 1 to 0. Decrease on the oxidation state means reduction.

    Ni passed from 0 to + 2. Increase on the oxidation state means oxidation.

    Conclusion:

    Substance being oxidized: Ni

    Substance being reduced: H
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