What is the molarity of a solution that contains 0.400 mol HCl in 9.79 l solution?

A. 0.0133 M

B. 0.0409 M

C. 0.959 M

D. 5.67 M

Option B, 0.0409 M

Explanation:

1) dа ta:

a) M = ?

b) n = 0.400 mol

V = 9.79 liters

2) Formula:

M = n / V (in liters)

3) Solution:

M = 0.400 mol / 9.79 liter = 0.04086 M

Since each data contain 3 significant digits, the answer must be reported with 3 significant digits. So, the correct answer is 0.0409 M, which is the option B.