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14 April, 05:37

Measurements show that the enthalpy of a mixture of gaseous reactants increases by 130. kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that - 137. kJ of work is done on the mixture during the reaction.

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  1. 14 April, 08:08
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    167 kJ

    Explanation:

    Given parameters

    Change in enthalpy = 130 kJ (decrease)

    Work done = - 137 kJ

    Change in energy, / delta = ?

    From the first law of thermodynamics:

    ΔH = ΔE + PΔV,

    Where, ΔH = change in enthalpy

    ΔE = change in Internal energy

    Substituting values into the above formula -

    130 kJ = ΔE + - 137 kJ

    130 kJ = ΔE - 137 kJ

    therefore,

    ΔE = (130 + 137) kJ

    ΔE = 167 kJ

    Therefore, the change in energy of the gas mixture during the reaction is 167 kJ.

    Since the value of energy change Is positive, therefore this Is endothermic reaction
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