A gas has a mass of 3.82 g and occupies a volume of 0.854 L. The temperature in the laboratory is 302 K, and the air pressure is 1.04 atm. Calculate the molar mass of the gas.

m = given mass of gas = 3.82 g

M = molar mass of gas = ?

T = temperature of laboratory = 302 K

P = air pressure = 1.04 atm = 1.04 x 101325 pa

V = volume of gas = 0.854 L = 0.854 x 10⁻³ m³

using the ideal gas equation

PV = (m/M) RT

inserting the above values

(1.04 x 101325) (0.854 x 10⁻³) = (3.82/M) (8.314) (302)

M = 106.6 g

hence the molar mass of the gas comes out to be 106.6 g