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29 January, 21:12

How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in the single replacement reaction below? Be sure to show the work that you did to solve this problem.

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  1. 29 January, 22:13
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    Answer is: 25.84 milliliters of sodium metal.

    Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

    d (Na) = 0.97 g/mL; density of sodim.

    m (NaOH) = 43.6 g; mass of sodium hydroxide.

    n (NaOH) = m (NaOH) : M (NaOH).

    n (NaOH) = 43.6 g : 40 g/mol.

    n (NaOH) = 1.09 mol; amount of sodium hydroxide.

    From chemical reaction: n (NaOH) : n (Na) = 2 : 2 (1: 1).

    n (Na) = 1.09 mol.

    m (Na) = 1.09 mol · 23 g/mol.

    m (Na) = 25.07 g; mass of sodium.

    V (Na) = m (Na) : d (Na).

    V (Na) = 25.07 g : 0.97 g/mL.

    V (Na) = 25.84 mL.
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