The volume of a gas is 200 mL at 315.0 kPa pressure. What will the volume be

when the pressure is reduced to 50.0 kPa, assuming the temperature remains

constant?

1260 mL

Explanation:

Given dа ta:

Initial volume of gas = 200 mL

Initial pressure = 315.0 KPa

Final volume = ?

Final pressure = 50.0 KPa

Solution:

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

315 KPa * 200 mL = 50 KPa * V₂

V₂ = 63000 KPa. mL / 50 KPa

V₂ = 1260 mL