What is the correct unabbreviated electron configuration of the following?:

vanadium:

strontium:

carbon:

The correct unabbreviated electron configuration is as below

Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2

Strontium - 1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2

Carbon = 1S2 2S2 2P2

Explanation

vanadium is in atomic number 23 in the periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2

Strontium is in atomic number 38 in periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4s2

Carbon is in atomic number 6 in periodic table therefore its electron configuration is 1s2 2s2 2p2