Limestone is primarily a crystal form of caco 3 . How many moles of oxygen are in a 1.25 mol sample of caco 3 ? Only include the numerical value in your answer. Do not include units.

Answer: 0.0375

Explanation:

1 mole of CaCO3 contains 3 moles of oxygen.

Molar mass of CaCO3 = [40 + 12 + (16*3) ] = 100g/mol.

From the stoichiometry,

1 mole = molar mass

100moles of CaCO3 = 3moles of oxygen

1.25 moles of CaCO3 = x moles of oxygen

X = (1.25 * 3) / 100 = 0.0375 moles of oxygen

Therefore, 0.0375 moles of oxygen is present in 1.25 moles of CaCO3

As the molecular formula of CaCO₃ suggested, that there are 3 moles of oxygen are there in 1 mole of CaCO₃.

So in 1.25 mol of CaCO₃ contains=1.25 * 3 moles of oxygen

=3.75 moles of oxygen

So there are 3.75 moles of oxygen are there in 1.25 mol of CaCO₃.