Ask Question
10 October, 21:06

If you have 112 g of Ni and 112 g of AgNO3, how many atoms of silver would be produced?

+1
Answers (1)
  1. 10 October, 21:12
    0
    3.97 * 10²³ atoms of Ag

    Explanation:

    Given dа ta:

    Mass of Ni = 112 g

    Mass of AgNO₃ = 112 g

    Atoms of silver produced = ?

    Solution:

    Chemical equation:

    Ni + 2AgNO₃ → 2Ag + Ni (NO₃) ₂

    Number of moles of Ni:

    Number of moles = mass / molar mass

    Number of moles = 112 g/58.7 g/mol

    Number of moles = 2 mol

    Number of moles of AgNO₃:

    Number of moles = mass / molar mass

    Number of moles = 112 g/169.87 g/mol

    Number of moles = 0.66 mol

    Now we will compare the moles of Ag with both reactants.

    AgNO₃ : Ag

    2 : 2

    0.66 : 0.66

    Ni : Ag

    1 : 2

    2; 2*2 = 4 mol

    Number of moles of Ag produce by AgNO₃ are less so it will limiting reactant and limit the yield of Ag.

    I mole = 6.022 * 10²³ atoms

    0.66 mol * 6.022 * 10²³ atoms / 1 mol

    3.97 * 10²³ atoms of Ag
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If you have 112 g of Ni and 112 g of AgNO3, how many atoms of silver would be produced? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers