Ask Question
14 May, 11:24

10. Copper (i) bromide reacts with magnesium metal: 2 CuBr + Mg → 2 Cu + MgBrz

If 0.253 moles of magnesium react in this way,

a. How many grams of CuBr are consumed?

+4
Answers (2)
  1. 14 May, 11:44
    0
    72.611g

    Explanation:

    Step1:

    We'll begin by writing the balanced equation for the reaction. This is illustrated below:

    2CuBr + Mg → 2Cu + MgBr2

    Step 2:

    Let us calculate the mass of Mg in 0.253 mole of Mg. This is illustrated below:

    Molar Mass of Mg = 24g/mol

    Mole of Mg = 0.253 mole

    Mass of Mg = ?

    Mass = number of mole x molar Mass

    Mass of Mg = 0.253 x 24

    Mass of Mg = 6.072g

    Step 3:

    Let us calculate the mass of CuBr and the mass of Mg that reacted from the balanced equation. This is illustrated below:

    Molar Mass of CuBr = 63.5 + 80 = 143.5g/mol

    Mass of CuBr from the balanced equation above = 2 x 143.5 = 287g

    Molar Mass of Mg = 24g/mol

    Step 4:

    The mass of CuBr consumed by 0.253 mole (i. e 6.072g) of Mg can be obtained as follow:

    From the balanced equation:

    2CuBr + Mg → 2Cu + MgBr2

    287g of CuBr were consumed by 24g of Mg.

    Therefore, Xg of CuBr will be consume by 6.072g of Mg i. e

    Xg of CuBr = (287x6.072) / 24

    Xg of CuBr = 72.611g

    Therefore, 72.611g of CuBr is consumed by 0.253 mole of magnesium
  2. 14 May, 14:16
    0
    72.6 grams

    Explanation:

    I got this answer through stoichiometry. For every 1 mole of Mg, 2 moles of CuBr are consumed. Because of this, multiply the moles of Mg by 2. Then, convert moles to grams.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “10. Copper (i) bromide reacts with magnesium metal: 2 CuBr + Mg → 2 Cu + MgBrz If 0.253 moles of magnesium react in this way, a. How many ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers