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1 October, 01:38

Determine the ph of a 0.62 m nh4no3 solution at 25°c. The kb for nh3 is 1.76 * 10-5.

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  1. 1 October, 05:06
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    ph = 4.73

    Explanation:

    Determine the pH of a 0.62 M NH4NO3 solution at 25C

    The Kb for NH3 is 1.76 x 10^-5

    NH4 + is the conjugate acid of the base NH3

    Ka for NH4 + = K water / K NH3 conjugate base

    Ka = 1 * 10⁻¹⁴ / 1.76 10⁻⁵

    = 5.68 * 10⁻¹⁰

    which is he Ka for

    NH4 + H2O - -> NH4OH + H⁺

    Ka = [NH4OH] [H+] / [NH4) + ]

    5.68 * 10⁻¹⁰ = [X] [X] / [0.62]

    X² = 3.52 * 10⁻¹⁰

    X = [H+] = 1.88 * 10⁻⁵

    p of that H + = 4.73

    ph = 4.73
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