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20 June, 04:34

If 22 mL of 0.137M MgCl2 is needed to completely react 15 mL of AgNO3 solution, what is the molarity of AgNO3?

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  1. 20 June, 05:38
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    The molarity of AgNO3 is 0.401 M

    calculation

    Step 1: write the chemical equation for reaction

    MgCl2 + 2AgNO3 → Mg (No3) 2 + 2 AgCl

    Step 2: calculate the moles of MgCl2

    moles = molarity x volume in liters

    volume in liters=22/1000 = 0.022 L

    molarity = 0.137 M or 0.137 mol/L

    moles is therefore = 0.137 mol/l x 0.022 L = 3.01 x10^-3 moles

    Step 3: use the mole ratio to determine the moles of AgNO3

    The mole ratio of MgCl2: AgNO3 is 1:2 therefore the moles of AgNo3 is

    = 3.01 x 10^-3 moles x 2/1 = 6.02 x 10^-3 moles

    Step 4: find the molarity of AgNO3

    molarity = moles / volume in liters

    volume in liters = 15/1000=0.015 L

    molarity is therefore = (6.02 x 10^-3) / 0.015 = 0.401 M
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