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25 September, 09:20

Calculate each of the following quantities. (a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate WebAssign will check your answer for the correct number of significant figures. g (b) Molarity of 597 mL solution containing 21.1 g of potassium iodide WebAssign will check your answer for the correct number of significant figures. M (c) Amount (mol) of solute in 145.6 L of 0.703 M sodium cyanide WebAssign will check your answer for the correct number of significant figures. mol

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  1. 25 September, 11:10
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    a) 7.40 grams

    b) 0.213 M

    c) 102 moles

    Explanation:

    (a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate

    Step 1: Data given

    Volume = 175.4 mL = 0.1754 L

    Molarity = 0.267 M

    Molar mass = 158.17 g/mol

    Step 2: Calculate moles

    Moles = molarity * volume

    Moles = 0.267 M * 0.1754 L

    Moles = 0.0468 moles

    Step 3: Calculate mass

    Mass = 0.0468 moles * 158.17 g/mol

    Mass = 7.40 grams

    b) Molarity of 597 mL solution containing 21.1 g of potassium iodide

    Step 1: Data given

    Volume = 597 mL = 0.597 L

    Mass = 21.1 grams

    Molar mass KI = 166.0 g/mol

    Step 2: Calculate moles KI

    Moles KI = 21.1 grams / 166.0 g/mol

    Moles KI = 0.127 moles

    Step 3: Calculate molarity

    Molarity = moles / volume

    Molarity = 0.127 moles / 0.597 L

    Molarity = 0.213 M

    (c) Amount (mol) of solute in 145.6 L of 0.703 M sodium cyanide

    Step 1: Data given

    Volume = 145.6 L

    Molarity = 0.703 M

    Step 2: Calculate moles

    moles = molarity * volume

    Moles = 0.703 M * 145.6 L

    Moles = 102 moles
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