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31 August, 06:17

Consider hydrogen atom in an excited state of 3s1. What is the energy of its electron

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  1. 31 August, 07:22
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    Given:

    Excited state electron configuration of H atom = 3s¹

    To determine:

    Energy of the electron in this state

    Explanation:

    The energy 'E' of an electron in a hydrogen atom occupying a level, 'n' is given by the formula:

    En = - E₀/n²

    where, E₀ is the ground state energy = 13.6 eV

    n = principle quantum number i. e. n = 1,2,3 ...

    Therefore,

    En = - 13.6/n² eV

    In this case for a 3s¹ configuration, n = 3

    E = - 13.6 / (3) ² = - 1.51 eV

    Ans: Energy of the electron in a 3s1 state is - 1.51 eV
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