A gas that occupies 50.0 liters has its volume increased to 68 liters when the pressure was changes to 3.0 ATM. What was the original pressure of the gas in ATM?

4.08 atm was the original pressure

Explanation:

When the temperature and the number of moles keeps on constant in 2 situations with a gas, we can apply this relation:

P₁. V₁ = P₂. V₂

It is an undirectly proportion, When the volume decrease, the pressure increase so if the pressue decrease, the volume will be increased.

P₁. 50L = 3 atm. 68L

As the volume was increased, the initial pressure must be higher than the final pressure.

P₁ = (3 atm. 68L) / 50L = 4.08 atm