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24 December, 18:56

The reaction for the burning of one type of match tip is as follows: P4S3 (s) + 8 O2 (g) P4O10 (g) + 3 SO2 (g) What volume of SO2 at STP can be produced by burning 1.00 g P4S3 in excess O2?

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  1. 24 December, 20:52
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    a] work out mass of 1 mole P4S3 - - call this Y grams

    b] eqtn tells you 1 mole P4S3 gives 3 moles SO2 [ = 3 x 22.4L at STP]

    c] by simple proportion

    1g P4S3 gives (3 x 22.4) / Y SO2 at STP answer
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