What is the final temperature of a 27.2-gram wooden block that starts at 23.4°C and loses 759 joules of energy? The specific heat capacity of wood is 1.716 joules/gram degree Celsius. Use the formula Q = mCΔT.

A. 7.1°C

B. 10.9°C

C. 16.3°C

D. 39.7°C

T = final temperature of the block

T₀ = initial temperature of the block = 23.4 °C

Q = energy lost from the wooden block = - 759 J

c = specific heat capacity of wood = 1.716 J / (g °C)

m = mass of the wooden block = 27.2 g

Heat lost from the block is given as

Q = m c (T - T₀)

inserting the values

- 759 = (27.2) (1.716) (T - 23.4)

T = 7.1 °C