Ask Question
25 April, 09:14

What is the final temperature of a 27.2-gram wooden block that starts at 23.4°C and loses 759 joules of energy? The specific heat capacity of wood is 1.716 joules/gram degree Celsius. Use the formula Q = mCΔT.

A. 7.1°C

B. 10.9°C

C. 16.3°C

D. 39.7°C

+4
Answers (1)
  1. 25 April, 11:19
    0
    T = final temperature of the block

    T₀ = initial temperature of the block = 23.4 °C

    Q = energy lost from the wooden block = - 759 J

    c = specific heat capacity of wood = 1.716 J / (g °C)

    m = mass of the wooden block = 27.2 g

    Heat lost from the block is given as

    Q = m c (T - T₀)

    inserting the values

    - 759 = (27.2) (1.716) (T - 23.4)

    T = 7.1 °C
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the final temperature of a 27.2-gram wooden block that starts at 23.4°C and loses 759 joules of energy? The specific heat capacity ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers