Ask Question
14 May, 13:09

Attempt 2 A sample of gas contains 49.16 % N 2 gas, 19.85 % Br 2 gas, 9.95 % CO 2 gas, and 21.04 % of an unknown gas. The average atomic mass of the gas mixture is 50.71 u. Calculate the atomic mass of the unknown gas.

+5
Answers (2)
  1. 14 May, 13:53
    0
    Atomic mass of unknown gas is 4u

    Explanation:

    Average atomic mass of a gas is defined as the sum of molecular mass * percentage of each component in the mixture.

    In the problem:

    50.71u = 28*49.16% + 159.8*19.85% + 44*9.95% + X*21.04%

    Where X is atomic mass of unknown gas

    50.71u = 49.86 + X*21.04%

    0.8469 = X*21.04%

    4u = X

    Atomic mass of unknown gas is 4u
  2. 14 May, 17:03
    0
    The atomic mass of the unknown gas is 3.982 u

    Explanation:

    Step 1: Data given

    A gas contains:

    49.16 % N2 gas

    19.85 % Br2 gas

    9.95 % CO2 gas

    21.04 % of an unknown gas

    The average atomic mass of the gas mixture is 50.71 u

    Molar mass of N2 = 28.0134 u

    Molar mass of Br2 = 159.808 u

    Molar mass of CO2 = 44.009 u

    Step 2: Calculate tthe atomic mass of the unknown gas

    50.71 = 0.4916 * 28.0134 + 0.1985 * 159.808 + 0.0995 * 44.009 + 0.2104 * X

    50.71 = 13.77138744 + 31.721888 + 4.3788955 + 0.2104 X

    0.83782906 = 0.2104X

    X = 0.83782906 / 0.2104

    X = 3.982 u

    The atomic mass of the unknown gas is 3.982 u
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Attempt 2 A sample of gas contains 49.16 % N 2 gas, 19.85 % Br 2 gas, 9.95 % CO 2 gas, and 21.04 % of an unknown gas. The average atomic ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers