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25 August, 01:57

A balloon filled with 1.22 L of gas at 286 K is heated until the

volume is 2.86 L while the pressure remains constant. What is

the temperature of the gas in Kelvin? Give your answer to the

nearest whole number.

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Answers (1)
  1. 25 August, 04:19
    0
    Answer: 670K

    Explanation:

    Given that,

    Original volume of gas V1 = 1.22 L

    Original temperature T1 = 286 K

    New volume V2 = 2.86 L

    New temperature T2 = ?

    Since volume and temperature are involved while pressure is constant, apply the formula for Charles law

    V1/T1 = V2/T2

    1.22 L/286 K = 2.86 L / T2

    Cross multiply

    1.22 L x T2 = 286 K x 2.86 L

    1.22T2 = 817.96

    Divide both sides by 1.22

    1.22T2/1.22 = 817.96/1.22

    T2 = 670.459 K (Round to the nearest whole number as 670 K)

    Thus, the temperature of the gas is 670 Kelvin
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