A solution in equilibrium with solid barium phosphate (ba3 (p o4) 2) is found to have a barium ion concentration of 0.0005 m and a ksp of 3.4 x 10-23. calculate the concentration of phosphate ion. 1. 2.6x10-7 2. 1.04x10-6 3. 5.2x10-7 4. 1.3x10-7 5. 2.7x10-13

Question

Chemistry

Aron Wiley

25 April, 09:55

A solution in equilibrium with solid barium phosphate (ba3 (p o4) 2) is found to have a barium ion concentration of 0.0005 m and a ksp of 3.4 x 10-23. calculate the concentration of phosphate ion. 1. 2.6x10-7 2. 1.04x10-6 3. 5.2x10-7 4. 1.3x10-7 5. 2.7x10-13

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Answers (1)

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Rubi Benson · Answer 1

Answer is: 3. 5.2x10-7.

Balanced chemical reaction (dissociation):

Ba₃ (PO₄) ₂ (s) → 3Ba²⁺ (aq) + 2PO₄³⁻ (aq).

[Ba²⁺ ] = 0,0005 M.

Ksp (Ba₃ (PO₄) ₂) = 3,4·10⁻²³.

Ksp = [Ba²⁺]³ · [PO₄³⁻]².

3,4·10⁻²³ = (0,0005 M) ³ · [PO₄³⁻]².

[PO₄³⁻] = √3,4·10⁻²³ : 1,25·10⁻¹⁰.

[PO₄³⁻] = 5,2·10⁻⁷ M.

Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.