If the gas inside the flask is cooled so that its pressure is reduced from 797.3 torr to a value of 715.7 torr what will be the height of the mercury in the open-end arm? (hint: the sum of the heights in both arms must remain constant regardless of the change in pressure.)

Question

Chemistry

Chris

5 February, 11:28

If the gas inside the flask is cooled so that its pressure is reduced from 797.3 torr to a value of 715.7 torr what will be the height of the mercury in the open-end arm? (hint: the sum of the heights in both arms must remain constant regardless of the change in pressure.)

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Chris · Answer 1

The differential pressure is

797.9 - 715.7 = 82.2 torr = 138815.25 Pa

The height of the mercury in the open-end arm is calculated using

ΔP = ρgh

The density of mercury is 13560 kg/m3

The height of the mercury is

138815.25 Pa = 13560 kg/m3 (9.81 m/s2) h

h = 1.04 m