Methanol burns in oxygen to form carbon dioxide and water. find delta h

Answer is: enthalpy is - 1276,8 kJ.

Chemical reaction: 2CH₃OH (l) + 3O₂ (g) → 2CO₂ (g) + 4H₂ O (g).

ΔH (CH₃OH) = - 238,7 kJ/mol.

ΔH (H₂O) = - 241,8 kJ/mol.

ΔH (CO₂) = - 393,5 kJ/mol.

ΔH (O₂) = 0 kJ/mol.

ΔHreaction = ∑ΔHproducts - ∑ΔHreactants

ΔHreaction = (2· (-393,5) + 4· (-241,8) - (2· (-238,7))

ΔH = (-787 - 967,2) + 477,4

ΔH = - 1276,8 kJ.