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14 March, 01:03

A 118.63 g sample of SrCl2·6H2O was heated and 34.81 grams of water were recovered from the sample. What percent of the original H2O remains in the sample following this heating?

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  1. 14 March, 01:43
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    Percentage mass of water in SrCl₂ ·6H ₂O

    = (6 x 18) / (88 + 35.5 x 2 + 6 x 18)

    = 40.4%

    Mass of water in sample originally₂:

    118.63 x 40.4%

    = 47.9 grams

    Percentage remaining = (47.9 - 34.81) / 47.9 x 100

    = 27.3%
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