For a given sample of ch3oh, the enthalpy change during the reaction is 82.3 kj. how many grams of methane gas are produced?

The equation is as follows;

2CH3OH (g) = 2CH4 (g) + O2 (g), ΔH = + 252.8 kJ

From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.

Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2*82.3) / 252.3

= 0.6524 moles

which is equivalent to 0.6524 * 16 = 10.438 g

There, the mass of CH4 produced will be 10.438 g