What is the number of copper atoms in 1naira coin which weighs 7.39g assuming the material of which the coil is made is 86% copper Na=n/n number of moles/n

Question

Chemistry

Gunner Weiss

27 December, 20:44

What is the number of copper atoms in 1naira coin which weighs 7.39g assuming the material of which the coil is made is 86% copper Na=n/n number of moles/n

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Ezekiel Meyer · Answer 1

Answer is: 6,023·10²² atoms of copper.

m (coin) = 7,39g.

ω (Cu) = 86% : 100% = 0,86.

ω - mass percentage of copper in coin.

m (Cu) = ω· m (coin) = 0,86·7,39g = 6,355g.

n (Cu) = m:M = 6,355g : 63,55g/mol = 0,1mol.

N (Cu) = n·Na = 0,1·6,023 * 10²³ = 6,023·10²².

Na - Avogadro's number.