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12 July, 18:40

A 1.20 g sample of water is injected into an evacuated 5.00 l flask at 65°c. part of the water vaporizes and creates a pressure of 187.5 mmhg. what percentage of the water vaporized?

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  1. 12 July, 21:57
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    Assume that the water vapor is an ideal gas. So,

    PV = nRT

    For conversion, 760 mmHg = 101325 Pa and 1,000 L = 1 m³

    (187.5 mmHg) (101325 Pa/760 mmHg) (5 L) (1 m³/1,000 L) = n (8.314 m³Pa/molK) (65+273 K)

    Solving for n,

    n = 0.0445 mole water

    Since the molar mass of water is 18 g/mol,

    Mass of water vaporized = 0.0445*18 = 0.8 g water vaporized

    Hence,

    Percentage of water vaporized = 0.8/1.2 * 100 = 66.7%
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